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  2. 4 Solutions of the 1D Schrödinger equation We now ...

    www.qi.damtp.cam.ac.uk/files/Adrian/notespart2.completed.2019.pdf
    6 Nov 2019: A cos(ka) B sin(ka) = 0 (4.23). and hence. A cos(ka) = 0 and B sin(ka) = 0. ... or B = 0 , cos(ka) = 0 ,. ψ(x) = A cos(kx) , k =nπ.

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