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8 Oct 2015: x = A cos ωt B sin ωt a cos(ωt ϵ) Peiωt Qeiωt, (2). ... The solution isx = A cos ωt B sin ωt. Initially, x = a and ẋ = 0, so.

8 Oct 2015: The other end,B, is fixed. The particle moves in a horizontal circle a distance d below B. ... cos θ,. where cos θ = d/l. 2 A particle rests at the top of a smooth sphere.

31 Dec 2015: ex. ez. ) a2 y(ez. ey eyez). (16). The contour of the elliptical cross section can be parameterized as x = a cos , y = b sin , with0   2. ... a sin e. x. b cos eypa2sin2 b2cos2. , n =b cos e.

9 Nov 2015: 87 –. while the jump condition gives. B( cos(1 ξ)) A cos ξ = 1. ... The generalsolution of this homogeneous equation c1 cos x c2 sin x and the inhomogeneous boundary.

26 Oct 2015: When λ 0 then X(x) = a sin(λx) b cos(. λx) solves X′′ = λX. ... λx B cos. λx, but if we impose the boundary condition y(1) = y(1) then.

4 Aug 2015: where. Vn = (An Bny)eny sin nξ (Cn Dny)eny cos nξ.(11). ... 3), is given by. rs = (δ ρ cos θ )x ρ sin θ y z z, δ = b sin k(z ct ),(18).

13 Jan 2015: repr. oduc. ed w. ithou. t per. mis. sion. In the last step, we used spherical polars with z = r cos θ. ... is. φ = a b. r. (90). Next we have solutions, like the dipole potential, cos θ,.

30 Nov 2015: plex exponential eiθ = cos θ i sin θ. This is periodic with period 2π, and so we can view. ... f̂0. n=1. an cos nθ bn sin nθ. (1.14). 4Recalling that the orthonormal functions were {einθ/.