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  2. K. A. Seffen1Department of Engineering, University of Cambridge,…

    www-g.eng.cam.ac.uk/advancedstructures/files/pdf/2014JAM.pdf
    15 Jun 2015: R1 R þ R cos bR1 cosðp=nÞ. ) R1R2. pnb. sin btanðp=nÞþ 1 cos b. ... n2 bn=p. 1 cos b þðsin bÞ= tanðp=nÞ 1 (3). It is not possible to solve explicitly for n, so we specify n and cal-culate n for given
  3. acs_nn_nn-2015-02502g 1..10

    www-g.eng.cam.ac.uk/nms/publications/pdf/acsnano2E5b02502.pdf
    31 Jul 2015: polarization of the incident light and the polarization. of the Raman signal, I(LBM) = a2 cos(φ)2 (see Methods). ... Thus, I(LBMs) in t(mþn)LG (m 6 n) is. I(LBMs). [cos φ sin φ 0]a 0 00 a 00 0 b.

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