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12 Oct 2021: The least such n iscalled the order of g.). (b) Show that there exists a positive integer n such that gn = e for all g G. ... θ(g) = e for all g D2n. Find all homomorphisms D2n Cnwhen n is even.

25 Aug 2021: of Jb(F) of maximal volume.(2) Show that all the stabilizers have the maximal volume. ... We now fix a choice of Haar measure on G(F) such that all Iwahori sub-groups of G(F) have volume 1.

29 Oct 2021: Let X be a Markov chain containing an absorbing state s to which all other states lead (i.e., j sfor all j). ... i < b, where 0 < λi, µi < 1 for all i, and λi µi = 1 for 1 i < b.Show that this process is time-reversible in equilibrium.

29 Nov 2021: 5. Show that T B(H) is normal iff ‖Tv‖ = ‖Tv‖ for all v H. ... 13. Let U B(H) unitary. Show that for all x H, the sequence n1n1.

30 Oct 2021: Assume that for some K > 0 we have. |ψ(t,x) ψ(t,y)|6 K‖xy‖ for all t [a,b] and all x,y BR(z). ... xn1) BR(z). Then ϕ is continuous and satisfies‖ϕ(t,x) ϕ(t,y)‖6 (K 1)‖xy‖ for all t [a,b] and all x,y BR(z).

16 Mar 2021: Homotopy Theory, Examples 4. Oscar Randal-Williams. Lent 2021. All cohomology is with Z/2-coefficients unless otherwise specified. ... i) Show that Sqi : Hni(M) Hn(M) = Z/2 is zero for all i > 0.

15 Oct 2021: a) f L1(Rn), g Ck(Rn) with supRn |Dαg| < for all |α| k. ... Deduce Hölder’s inequality:Rn|f(x)g(x)|dx ||f||p ||g||q , for all f L. p(Rn), g, Lq(Rn).

6 Aug 2021: Define τxφ by:. τxφ : C,y 7 φ(y x). (1.2). Then there exists > 0 such that τxφ Ckc () for all x B(0). ... for all x (a,b).Then: b.

8 Aug 2021: x. for all x so (λA)B = λ(AB). Again(. A(λB)). x = A(. ( ... for all x Rn so A B = B A).(iii) Observe that.

21 Nov 2021: Thus B(y,r) E for all r > 0 and E is not. ... as m. Thusa B(xj,δj) Uj. for all j 1 and. a j=1.

8 Oct 2021: We write B′ for the totally definite quaternion algebra which agrees with B at all finite places. ... We fix a totally indefinite quaternion algebra B over F which is split at all the places above p.Let S Σ Σp be a subset of even cardinality.

21 Nov 2021: i) Show that, if dY (a,b) = d(a,b) for all a, b Y , then (Y,dY ) is ametric space. ... B(p,q) B(p,q) for all (p,q) E. andA(p,q) A(p,q) for all (p,q) E.

15 Feb 2021: The only case left is when all the eigenvalues of A are equal to1. ... Z. This covers all cases and shows that U doesnot contain any non-trivial subgroup.

15 Oct 2021: for all x,y,z Rn and a R. b) For t R and x,y Rn, show that:. ... ii) For all f C0([a,b]), if a R, then ||af||C0 = |a| ||f||C0.

15 Oct 2021: Define τxφ by:. τxφ : C,y 7 φ(y x). (1.2). Then there exists > 0 such that τxφ Ck0 () for all x B(0). ... u[φ]| C supxK. |α|N. |Dαφ(x)| , for all φ C0 (K).

15 Oct 2021: hi φ Diφ in S , as h 0. b) First, we note the following simple inequality which holds for all x,y Rn:. ... for all x K, so that:. 1 6 (1 R)1 |x g|.

22 Jan 2021: Thus B(y,r) E for all r > 0 and E is not. ... i) Show that, if dY (a,b) = d(a,b) for all a, b Y , then (Y,dY ) is ametric space.

19 Jan 2021: so one can just check all possible bijections to see whetherthey’re isomorphisms. ... such that:. for all f : X Y , f = idY f = f idX; and.

30 Apr 2021: iii) There exists δ3 > 0 s.t. for all x,y,z,t X,. ... for all p X and r > 0, ifα is a path in X r B(p,r) between two points x,y S(p,r), then. (

15 Oct 2021: Define τxφ by:. τxφ : C,y 7 φ(y x). (1.2). Then there exists > 0 such that τxφ Ckc () for all x B(0). ... for all x (a,b).Then: b.

11 Jan 2021: Its image is the diameter [1, 1] ofB. Since rotations centred at 0 are isometries of B, all diameters are shortest paths of B. ... d(0,z). Therefore, f̃ stabilises all hyperbolic circles centred at 0 in B.

15 Oct 2021: All bodies in a gravitationalfield accelerate at the same rate regardless of their mass. ... is a Killing field: in fact we have that µVν = 0 for all µ,ν.

15 Oct 2021: for all x, y, z 2 Rn and a 2 R. ... x. Supposethat the x. i. satisfy ||xi. || < r for all i and some r > 0.

16 Mar 2021: 5. Compute H(K(Z,k); Q) for all k. [Hint: As usual use PK(Z,k) K(Z,k) and theequivalence K(Z,k) ' K(Z,k 1).]. ... inducing an isomorphism on H(; R), and hencethat πi(X)R = πi(Sn)R for all i.

10 Feb 2021: vn s.t. for all i, there is an edge ei betweenvi and one of the vertices v1,. ... The string matching problem is to find all occurrences of P in T.

15 Oct 2021: Questions marked () are optional. 2. b) For all x 2 A, for all i 2 N there exists > 0 such that:. ... R such that f(x) = ˜f(x) for all x 2 (a, b).

19 Jan 2021: 5. Show that T B(H) is normal iff ‖Tx‖ = ‖Tx‖ for all x H. ... 13. Let U B(H) unitary. Show that for all x H, the sequence n1n1.

23 Nov 2021: 7. Find an injection from R2 to R. Is there an injection from the set of all real sequences to R? ... Is there an uncountable collection T of subsets of N such that A B isfinite for all distinct A,B T?

7 Oct 2021: algebra. 1.2. Show that the following sets of subsets of R all generate the same σ-algebra:(a) {(a,b) : a < b}, (b) {(a,b] : a < b}, (c) {(,b] : b ... Show that. (a) C is uncountable and has Lebesgue measure 0,(b) for all x [0, 1], the limit F(x) =

13 Oct 2021: Here m, n, a, b should be understood as ranging over all natural numbers.). ... i) 1n = n 1 for all n;(ii) m1 = (m1)2 for all m > 1;.

12 Oct 2021: Show that G can be decomposedinto cycles if and only if all degrees of G are even. ... Show that there is a partition V = AB so all the vertices inthe graphs G[A] and G[B] are of even degree.

19 Jan 2021: Wemay say that T is generated by B. A neighbourhood basis1 at a point x X is a collection Bx of open subsets ofX, all containing x, such that any open ... for all B1,B2 B and for all x B1 B2 there exists some B3 B suchthat x B3 B1 B2.

8 Oct 2021: 11. Hölder inequalities to bound each term of the sum. Let (a,b) [1,]2 such that b a′, thenfor all (k,) Z2,. ... From Riesz representation Theorem, there exists T(x′) Hsuch that. 〈x′,T(x)〉B′B = (x | T(x′))H for all x H.