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30 Oct 2012: Fleming and B.B. Roberts on rock, filming https://www.freezeframe.ac.uk/collection/british-graham-land-expedition-collection/p51-8-q006 xmlrpcuser Thu, 05 Feb 2009 22:28:54 0000 ... Fleming and B.B. Roberts on rock, filming Reference: P51/8/Q006 Reference

30 Oct 2012: Roberts photographing elephant seal Reference: P51/8/R007 Reference: P51/8/R007 Title: B.B. Roberts photographing elephant seal Description: plastic negative Collection: British Graham Land Expedition 1934-37 Summary text: ... spanspan

30 Oct 2012: Roberts with Peter (cat) on ‘Penola’ Reference: P51/8/R009 Reference: P51/8/R009 Title: B.B. ... He has […] div class='image-page' div class='top-metadata' pspan class='mdk-Title'Title: /spanspan class='mdv-Title'B.B.

30 Oct 2012: Ryder and B.B. Roberts Reference: P51/8/G061 Reference: P51/8/G061 Title: Pram by beach, Penguin Island, South Shetlands, with L.C.D. ... Ryder and B.B. Roberts Description: plastic negative Collection: British Graham Land Expedition 1934-37 Summary text:

15 Aug 2012: the vector p has distribution given by Pp,(b) if p1 p2 then p1 p2. ... Take a = b = pc(T) for some small positive. Then choose largeenough so that a0 > pc(T).

15 Oct 2012: possible area is an arc of a circle passing through A and B. ... where n = n(s) and b = b(s) are the normal and binormal vectors of α.

15 Aug 2012: For A,B Zd, we say that A is connected to B if thereexist a A and b B such that a b; in this case, we write A B. ... We saythat A is fully connected to B if, for all b B, there exists a A such that a b;in this case, we write A fc B.

15 Aug 2012: For A, B V , we write AH B if either A B 6= or there exist a A and b B. ... 0 otherwise,. where A B means that there exists a A ( V ) and b B ( V ) such that a and bare in the same component of the random hypergraph (V, η(

6 Nov 2012: London, Sage. Francis, B. & Skelton, C. (2005). Reassessing gender and achievement: questioning contemporary. ... Hart, B., & Risley, R. T. (1995). Meaningful differences in the everyday experience of Young.

8 Mar 2012: b) Pψ(x) = λψ(x) and P 2ψ(x) = ψ(x) λ2 = 1. ... This gives. Aκ cos κa. A sin κa=. B k cos (ka δ0).