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31 Jan 2002: Searching for the optimum Root-Goal path. The methods of the previous section found some path between root and goal. A rather harder problem is to find the best path. For this we need to exploit the cost figures in the graph. British Museum. This

27 Aug 2002: xO:N"I(B B[CCFN[CjA@R[kND@5OQH5B"s ilkJFRO:BR[kCI(OQB[RDN[OQ5>5RDO:@H@]ºRDk5CR[@RFV ... Hc?5N[@5e"CBDBS@]NFRDCP¤ÌFHJIB[>?5?J@B[CSOQRR"FCB-R[OQXC=RD@Py-FVQFe"N[@B[B-R[kCuVFH5Ch¤ÇB[BD>5XOQH5¿R[kJFR-R[k5C?JCfI

24 Sep 2002: 1y wŽ. msyj s 1q j 2 j 3 j 4 jw q5w q5w q wq b b jÝ1 2 5j1y wŽ. ... P a, d s b 2 r q b b r q b 2 r , 5.8Ž.

25 Nov 2002: But the map (a,b)-->(b,a) is easily seen to be a bijection between AxB and BxA, from which it follows that BxA has cardinality mn. ... If m=1 then the result is obvious, since the map (1,x)-->x is a bijection between AxB and B, B has cardinality n, and

20 May 2002: 15. p. 243, lines 6 and 9: replace "(., f((r - 1)b/N /- |B_r| (b/N)2))" by "(., f((r - 1)b/N) /- |B_r| (b/N)2)". ... the brackets are misplaced). 16. p. 247, line 6: delete "<= B b3 N(-2)" (I am not quite sure here.).

16 May 2002: 4- & "4-2. 2 @ 4-8. 4-3/ 0 B-/-C 4-3. F 4-3. ... $ B3//C : % % , " " % " B83C " >! ( " ". 5B B. B CB. % " % &( B CB # //$ ,? #$. K% " %. ( K% # $. % #$ (. D % D. " % D. 4-. 454 4 6 7 /%&0 ',8'%9. %

23 Sep 2002: Th. 10DR R. B. B. WARDYPlato Ion. W. 12 (4L, weeks 1–4). ... Philosophy (Paper 8)DR R. B. B. WARDYPlato Republic 473–535 (16L). Tu.

31 Oct 2002: n2. (b) Let X be any random variable which takes on values 0,1,2,. ... a) Determine the equilibrium points. (b) Determine the stability of each of the equilibrium points.

20 May 2002: Thus, there is anisometry T , equal to either S or RS, with T(A) = A′, T(B) = B′ and T(C) = C′. ... points A = A,B = B,C = C. These lines divide S2 into 8 triangular regions.

21 Jun 2002: A = {(0,a,b,b,a)} k5. 13. The family of curves X(5) X(5) is defined by quadrics. ... By Lemma 3.3(i) we have. γ : (0 : a : b : b : a) 7 (0 : a′ : b′ : b′ : a′).