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19 Oct 2013: d T T T TV V V V V. b V VW V VX V V V V V VX VT e TgfV VX V V. ... h?h T T T TikjmlnjolEp [:q l VX VX b b VX Vc VX V r!s t.

6 Mar 2013: b. Thus two linearly independent solutions of Legendre’s equation can be written, in the casewhen m is not an integer (so that the exponents at the origin do not differ ... a(a 1)b(b 1). c(c 1). z2. 2! 2.

26 Jul 2013: b) Two dimers. We now consider the case of two dimersa and b. ... 482 2d3, 3a. V = ̄ab2 b1b1b2. ̄ba2 a1. a1a2 f a f b.

19 Aug 2013: Rotation of particles – rigid and dilute. Spheroid: axes a, b, b, aspect ratio r = ab. ... Averaged stress. σ = pI 2µE 2µφ[AE : 〈pppp〉. B(E 〈pp〉 〈pp〉E) CE FDrot〈pp〉].

5 Oct 2013: Toquantify this, we consider the condition number κ(B) =‖B‖‖B1‖. The following lemma is also found in [2]:. ... Technical reportNA2010/07, DAMTP, University of Cambridge, 2010. [2] B. Adcock and A.

26 Jul 2013: 3(b) denoting the 1=. ffiffiffiffiN. pisotropy. that is expected in our system. ... The case shown is for a puller swimmer (b 1) witha volume fraction / 0.01.

18 Jul 2013: B B. However, for our non-Abelian magnetic field, B B is simply a gaugetransformation. ... B. 2 ξi (k)0. (1.1). ψi =4. B. 2π. dk. 2πexp.

5 Oct 2013: Toquantify this, we consider the condition number κ(B) =‖B‖‖B1‖. The following lemma is also found in [2]:. ... Technical reportNA2010/07, DAMTP, University of Cambridge, 2010. [2] B. Adcock and A.