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30 Jan 2009: Use theBaker-Campbell-Hausdorff formula for exp C = exp A exp B in the form C = A B 12 [A, B] 112 ([A, [A, B]] [B, [B, A]]). ... cr. bs= λsa(b) µar(c) , µar(c) =. baϕr(c, b). b=0. , µar(c)λr b(c) = δab.

20 Jan 2009: MATHEMATICAL TRIPOS PART IB. ELECTROMAGNETISM. Examples 2. 1. A potential difference V is maintained between two coaxial cylinders of radiir = a, b, b > a and the gap a < r < b is ... Repeat the calculation in spherical geometry, i.e. for concentric

9 Jan 2009: E B) = (B)E (E)B E(B) B(E). Position vector: let r or ri denote the position vector, and r = |r|. ... φ) dl = φ(b) φ(a). 1. Curl in curvilinear coordinates (ξ1, ξ2, ξ3):.

9 Apr 2009: Φ =. S. B dS, (3). then we get Faraday’s Law of induction. ... B2dτ. (9). It can easily be seen, using the expression for L above and (7) for B = |B|, that the twoexpressions for the magnetic energy W give the same result in

29 Jan 2009: the direction of the normal b, |b| = 1 to the plane,is arbitrary. ... We get. (B+ B).tl = µ0s.bl. (B+ B).n b = µ0s.b.

23 Jul 2009: find that it is not necessary to know the tensors A , B and C in full detail, because the final answer only depends on the combination. ... w - [G+&A-l.B : B T A - l G ]. p(4.rcvt)$ vt. Finally we recall t h a t the angular-velocity autocorrelation

21 Jul 2009: J. HINCH’ A N D B. S. BHATT? Department of Applied Mathematics and Theoretical Physics, University of Cambridge,. ... Hinch and B. S. Bhatt. 1.6 I 1 1.4. 1.2. I.

23 Jul 2009: B : b = [3/4(2n l ) ( n l)In/2n, c = 0. ... A similar conclusion applies to c, with b = 0 and m replacing n.

31 Jul 2009: Thus. B = (B,),-dd.B-B.dddd(d.B.d). The equation governing the development of the full tensor B is then found to be. ... 2(d’d’. E. B B. E. d’d’) o(cY2). ( 1 4 b ) These results are not dependent in any essential way on the detailed nature of the

8 Jul 2009: B′ cos KX instead of A and B, with solution. N (0) ce(. ... Q(1)t= cuN (1)Θ. t. =cec. 2uΘ. 2a. 22(A A′ 1. 4(B B′).