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14 Sep 2006: The used costterm is thusI? £ F x Jt! #" tx Z £ «b«' Z BB aº B'B z»(17)where. ... I? " F B'B? s aò7µ F ÛóÌô4B'B. A partition of the state space is given by theVoronoi diagram defined by these nodes, seefigure 13a.ñ Partitioning the eigenspace

28 Oct 2006: b) Suppose that B = 0; the vector field B(r) is said to be solenoidal. ... Then there exists anon-unique vector potential, A(r), such that. B = A.

27 Feb 2006: ngi{_bie|g?t}&X;phYXXq&ZY[X+]. u:/u&9qfYucwE9& :q&>j uc Efc;A :q&> uc 9&E U ... k&mnbi]n}ZY[X}&XlZ<X;h<{y_]nbi]pZZ<ggi¥&Zb?_]b?]b?eoZYXhY]nb?ZY_iXµt:gphY{eb?ZY_gi]vg?tZY[_wWt9bpEZA[nb?Z«}&gfXWqZY[_wWh<X+}&

8 Nov 2006: 4O:=<CKI@asgD6m{¡MO<>MK?b |7| IU6 J8;:U47L :@JMnMOD:@J¢{0:[ADIPM<=8;:ib |j b |g Sh,£?b | b |g SG[ADIPMub |7|; VT:iU6 J8;:U47L ... B64u<CKC º 1 jsgD6m{MO<>Mub |7|; U6 J8;:U47L :@I@G}<JDWWD:UMO:U47[tJD:nKMOIkCK[tKM@» t4O:=<ChJAD[aV :4ubvea¿>b b b d

27 Apr 2006: tems. In addition, crystals an d b u b b l es in m ag m as m a y b e distributed so t h at they create stable den- ... G. F. G i b b , C. M. B. H e n d e r s o n , C.

31 Jan 2006: O. é{ê_êcë¥ìë¢íî_ïðKñzò_óôìë¢íî_ôOO WZnWYXZY}YwXr|.qRqXERq}fYasd eYfvWYX> ][w >qWYXmO KKI|.0X}d efpcv ][w nKRaWhX}uowuqRqusoaZnÝ 4e|Yd ef_o{uY4Rx[w RqdQWs dexXr >XuRqvr_b.

30 May 2006: 8 ). ( 4. 8 b ). = 0 (n-reven), (4 8 c ) and Fnr = t w ' q s ,. , g , , r B B / ( b r - b n ). (,4.9). We again suppress the argument. ... 4.10 b ) N ( - )" 23(nw cosh [)-$ sin ( w cosh inn - &I-) sen(?).

29 Sep 2006: b) SNRe contours at 2.0% strain. 2.5 Dynamic Resolution Selection procedure. ... and uncoloured noise Simulation B-15dB white noise,. etc. mean SNR is appended.

22 Oct 2006: Then there exist a A, b B and c C with ab = c.In particular, this is true if all of A, B and C have size greater than 2n8/9. ... Equivalently, there exist a A and b B suchthat ab = c, as claimed.

16 May 2006: Write B for Bi(A). Then for the set-systems A and B, wehave |A| = |A||A+||A4A+| and |B| = |B||B+||B4B+|.Now, |B| |A| and |B+| |A+| (by the ... system B = Ak satisfies |B| = |A|, |B| |A| and Bi(B) = B forall i.