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13 Feb 2019: a†a b†b = 1. (1.18). The Hamiltonian describing cavity polaritons for localised excitationsis then. ... H = Eg(n). 2. (. b†b a†a). ωcψ†ψ H′, (1.19). H′ =1N. (.

16 Oct 2003: rr$"B<1&u="B1"%=r.6r'[ l8?<7=([="F Q1=&1¡&u<="')?'="%:r'C1|1"%&h). ... 2:')?'="%: $"%' % ri"%$h)0A:mr|=<1&¡&,-8 "%' % ri"B<7@ <1@(h[=<1/. (

10 Nov 2010: Berry phase. φBerry =. 2= 2π. Aq(r) d2r. B = B he q(r). ... Skyrmion:. (B B) d2r = h. e 1 extra charge e.

24 Oct 2022: which matches the second form of the solution provided. A = a0 cos(φ) B = a0 sin(φ). ... a0 =A2 B2, φ = arctan (B/A). (16). 3.3 Why harmonic motion?

18 Jan 2014: a uniform static magneticfield perpendicular to the plane, B = Bẑ (E > 0, B > 0). ... 6]. (b) Compute the behaviour of the zero-field magnetic susceptibilityχ = (φ/B)|B=0 close to the transition (both above and below).

5 Feb 2019: B.4 Finding out about the singularities. 112. B.5 Vertex singularities. 112. ... 114. B.9 The volume singularity. 115. B.10 Evaluation of the tangents.

22 Jan 2024: It is better to focus on thefield B which is well behaved there. ... The motion we just describedcorresponds to a rotation in the a b plane.

30 Jul 2013: 1. 2. 3. C (. 10-. 2 /k B. ). b) ε = 0.05a) paramagnet. ... B 80, 140409(R) (2009). Overview Introduction Square Ice Kagomé-Ice & more Conclusions.

7 Jan 2019: 40 3 u4C7 849wde3 : 9 0 B: B. A B: r l y q y [ l q 849t: 7 /?4E 9tDMB: 3 7 3 B12N84/:e7 B?M9 rsu424E 9 : :A ... 9 2 ;9 2 3 ;.: 3 ;#6 9 3 4 ;.9 4 B>? ;:

7 Jan 2019: 2aχ 6m2χ = 1. where χ = m/B|B=0. Above the transition (a > 0), m(B = 0) = 0 andχ = 1/2a. ... Below the transition (a < 0), m(B = 0) =. a and χ = 1/4a.