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25 Oct 2011: 4. Let AB be a segment of straight line in the plane with endpoints A and B and let be afixed number strictly greater than the length of AB. ... ϕ(s,v) = α(s) r(n(s) cos v b(s) sin v. ),. where n = n(s) and b = b(s) are the normal and binormal vectors

31 Oct 2011: B}. Show thatif A and B are both closed and one of them is bounded then A B is closed. ... b) Is the space R[0, 1] of integrable functions on [0, 1], equipped with the uniform norm, complete?

31 Oct 2011: 4. Let AB be a segment of straight line in the plane with endpoints A and B and let be afixed number strictly greater than the length of AB. ... ϕ(s,v) = α(s) r(n(s) cos v b(s) sin v. ),. where n = n(s) and b = b(s) are the normal and binormal vectors

21 Feb 2011: Show that if there exists a vector e such that e,n(s),b(s) are linearly dependent forall s I, then α is a plane curve. ... ϕ(s,v) = α(s) r(n(s) cos v b(s) sin v. ),. where n = n(s) and b = b(s) are the normal and binormal vectors of α.

30 Oct 2011: Hint: argue by contradiction.). (6) Let f : B B be a continuous map from the open disc B = {(x, y) R2 : x2 y2 < 1} into it-self. ... . (a) Show that G is a metric on Q. (b) Assume n = 1.

31 Oct 2011: B}. Show thatif A and B are both closed and one of them is bounded then A B is closed. ... b) Is the space R[0, 1] of integrable functions on [0, 1], equipped with the uniform norm, complete?

29 Mar 2011: Our pointof departure is formula 6 which says there is an external isomorphism between〈A,A〉 and 〈B,B〉.(. ... We have now established that if there is an external isomorphism between〈A,A〉 and 〈B,B〉 then there is precisely one.

16 Aug 2011: family B A, we form the family φ(B) byreplacing appropriately chosen B B by CijB. ... Then there existsan injection φ : I(A) I(C) such that |φ(B)| = |B| for all B I(A).

29 Jul 2011: Then T is a maximal torus of I, and B, B. ... opare opposite. Borel subgroups containing it. Also U, Uop. are the unipotent radicalsof B, B.

25 Aug 2011: For B A [n](2) let. IB = {E I : E [n](2) = B}. ... LetU = {B B : B minimal, |B| < t}. andV = {B B : B minimal, |B| = t}.