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d %b %Y is a %A on the %d day of %B.") '12-02-03. ... module quickly demonstrates a modest performance advantage:. >>> from timeit import Timer >>> Timer('t=a; a=b; b=t', 'a=1; b=2').timeit() 0.57535828626024577 >>> Timer('a,b = b,a',

B. Floating Point Arithmetic: Issues and Limitations. Floating-point numbers are represented in computer hardware as base 2 (binary) fractions. ... B.1 Representation Error. This section explains the 0.1'' example in detail, and shows how you can perform

Copyright 1999-2000 Douglas Wright, doug@mech.uwa.edu.au. last updated 10 Jan 1999.

testing for real solutions to a quadratic d = bb - 4ac; if(d >= 0.0) { // real solutions root1 = (-b sqrt(d)) / (2.0a); root2 = (-b - sqrt(d)) / (2.0a); real_roots = true; } ... quotes switch(operation) { case '': result = a b; break; case '-': result =

a, b = b, ab. >>> # Now call the function we just defined:. ... result.append(b) # see below. a, b = b, ab. return result. >>>

C. B. B. B. C. C. C. C. C. C. X. ... y. Z. B. B. B. =. -. -. -. 0. 0.

Fibonacci numbers module def fib(n): # write Fibonacci series up to n a, b = 0, 1 while b < n: print b, a, b = b, ab def fib2(n): # return Fibonacci series ... up to n result = [] a, b = 0, 1 while b < n: result.append(b) a, b = b, ab return result.

a, b = b, ab. 1 1 2 3 5 8. ... print b,. a, b = b, ab. 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987.

Z. L. H, T. has. B. B. L = 203.2 x10. - ... 20.329. B N97. 20.329. 20.295. -. 0.166. 1%. -. 0.0338. 0.5.

HT-66/02/001/A. 1. Problem of reference. 1.1 Geometry. has. has. B. B. ... F. = 50.8 X 10 have. - 3. m. B = 25.4 X 10. -